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300=-0.5x^2+40-300
We move all terms to the left:
300-(-0.5x^2+40-300)=0
We get rid of parentheses
0.5x^2-40+300+300=0
We add all the numbers together, and all the variables
0.5x^2+560=0
a = 0.5; b = 0; c = +560;
Δ = b2-4ac
Δ = 02-4·0.5·560
Δ = -1120
Delta is less than zero, so there is no solution for the equation
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